0=2(x^2+3x-360)

Solution for 0=2(x^2+3x-360) equation:

0=2(x^2+3x-360)

We move all terms to the left:

0-(2(x^2+3x-360))=0

We add all the numbers together, and all the variables

-(2(x^2+3x-360))=0


We calculate terms in parentheses: -(2(x^2+3x-360)), so:

2(x^2+3x-360)

We multiply parentheses

2x^2+6x-720

Back to the equation:

-(2x^2+6x-720)


We get rid of parentheses

-2x^2-6x+720=0

a = -2; b = -6; c = +720;
Δ = b2-4ac
Δ = -62-4·(-2)·720
Δ = 5796
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5796}=\sqrt{36*161}=\sqrt{36}*\sqrt{161}=6\sqrt{161}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6\sqrt{161}}{2*-2}=\frac{6-6\sqrt{161}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6\sqrt{161}}{2*-2}=\frac{6+6\sqrt{161}}{-4}
$